Three guys spend the night at a very cheap hotel - it costs only $30 dollars for all three. They split the cost, paying only $10 each. After they get into their room, the desk clerk realizes he should only have charged $25 dollars. So, he gives the bellboy $5 to give back to the three guys. The bellboy is concerned on how they will split the $5. So the bellboy gives the guys only $3 and he keeps $2.
In the end, the guys only paid $9 each for the room for a total of $27 plus the $2 that the bellboy kept - equals $29. Where is the other $1??
Give me your thoughts or answer in the comment section.
Sunday, August 27, 2006
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2 comments:
This a math puzzle that can be solve 2 ways:
1. If you do it the logical way then you are missing 1 dollar. Each man payed 10 dollars and then recieved 1 dollar back which means 9 x 3 = 27 plus the 2 dollars that the bellboy kept = 29 dollars.
2. Each man gives 10 dollars
1st 10
2nd 10
3rd 10 = 30 dollars
the clerk gives back 5 dollars so
1st recieves 1 dollar
2nd recieves 1 dollar
3rd recieves 1 dollar = 3 dollars
and the bellboy keeps 2 dollars
3 + 2 = 5
It depends on how you do the math.
In reality you need to subtract the 2 dollars from the 27 = 25. It depends on how you do the math.
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